Cześć!
a)
[tex]3\dfrac{1}{5}=\dfrac{3\cdot5+1}{5}=\dfrac{15+1}{5}=\boxed{\frac{16}{5}}\\\\\\5\dfrac{4}{5}=\dfrac{5\cdot5+4}{5}=\dfrac{25+4}{5}=\boxed{\frac{29}{5}}[/tex]
b)
[tex]7\dfrac{3}{10}=\dfrac{7\cdot10+3}{10}=\dfrac{70+3}{10}=\boxed{\frac{73}{10}}\\\\\\2\dfrac{9}{10}=\dfrac{2\cdot10+9}{10}=\dfrac{20+9}{10}=\boxed{\frac{29}{10}}[/tex]
c)
[tex]4\dfrac{5}{9}=\dfrac{4\cdot9+5}{9}=\dfrac{36+5}{9}=\boxed{\frac{41}{9}}\\\\\\5\dfrac{8}{9}=\dfrac{5\cdot9+8}{9}=\dfrac{45+8}{9}=\boxed{\frac{53}{9}}[/tex]
d)
[tex]8\dfrac{1}{7}=\dfrac{8\cdot7+1}{7}=\dfrac{56+1}{7}=\boxed{\frac{57}{7}}\\\\\\9\dfrac{6}{7}=\dfrac{9\cdot7+6}{7}=\dfrac{63+6}{7}=\boxed{\frac{69}{7}}[/tex]
e)
[tex]10\dfrac{1}{3}=\dfrac{10\cdot3+1}{3}=\dfrac{30+1}{3}=\boxed{\frac{31}{3}}\\\\\\20\dfrac{2}{3}=\dfrac{20\cdot3+2}{3}=\dfrac{60+2}{3}=\boxed{\frac{62}{3}}[/tex]
f)
[tex]100\dfrac{1}{10}=\dfrac{100\cdot10+1}{10}=\dfrac{1000+1}{10}=\boxed{\frac{1001}{10}}\\\\\\50\dfrac{9}{10}=\dfrac{50\cdot10+9}{10}=\dfrac{500+9}{10}=\boxed{\frac{509}{10}}[/tex]
