Cześć!
Poziom A
[tex]\frac{2}{3}+2\frac{1}{3}=2\frac{3}{3}=2+\frac{3}{3}=2+1=3\\\\2\frac{7}{8}+1\frac{4}{8}=3\frac{11}{8}=3+\frac{11}{8}=3+1\frac{3}{8}=4\frac{3}{8}[/tex]
Poziom B
[tex]\frac{5}{8}+\frac{1}{10}=\frac{25}{40}+\frac{4}{40}=\frac{29}{40}\\\\\frac{3}{4}+\frac{1}{6}=\frac{9}{12}+\frac{2}{12}=\frac{11}{12}[/tex]
Poziom C
[tex]2\frac{3}{4}+1\frac{2}{3}=2\frac{9}{12}+1\frac{8}{12}=3\frac{17}{12}=3+\frac{17}{12}=3+1\frac{5}{12}=4\frac{5}{12}\\\\1\frac{3}{4}+2\frac{5}{6}=1\frac{9}{12}+2\frac{10}{12}=3\frac{19}{12}=3+\frac{19}{12}=3+1\frac{7}{12}=4\frac{7}{12}[/tex]
Poziom D
[tex]2,2+\frac{1}{4}=2,2+\frac{25}{100}=2,2+0,25=2,45\\\\1\frac{1}{2}+0,125=1\frac{1}{2}+\frac{125}{1000}=1\frac{1}{2}+\frac{1}{8}=1\frac{4}{8}+\frac{1}{8}=1\frac{5}{8}[/tex]
Poziom E
[tex]0,1+\frac{1}{6}+\frac{7}{12}+0,4=0,5+\frac{2}{12}+\frac{7}{12}=\frac{1}{2}+\frac{9}{12}=\frac{6}{12}+\frac{9}{12}=\frac{15}{12}=\frac{5}{4}=1\frac{1}{4}\\\\0,5+\frac{3}{17}+\frac{1}{2}=0,5+\frac{3}{17}+0,5=1+\frac{3}{17}=1\frac{3}{17}[/tex]
