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3,5 + (2 i 1/3 - 3,2) do potęgi 2 : 2,02 - 5 =
PLS NA TERAZ
100 P

Odpowiedź :

Magdaviz

Odpowiedź:

[tex]3,5+(2\frac{1}{3}-3,2)^2:2,02-5=3,5+(\frac{7}{3}-\frac{32}{10})^2:\frac{202}{100}-5=3,5+(\frac{7}{3}-\frac{16}{5})^2:\frac{101}{50}-5=\\\\=3,5+(\frac{35}{15}-\frac{48}{15})^2:\frac{101}{50}-5=3,5+(-\frac{13}{15})^2:\frac{101}{50}-5=3,5+\frac{169}{225} :\frac{101}{50}-5=\\\\=3,5+\frac{169}{\not225_{9}}\cdot\frac{\not50^2}{101}-5=-1,5+\frac{338}{909}=-\frac{15}{10}+\frac{338}{909}=-\frac{3}{2}+\frac{338}{909}=-\frac{2727}{1818}+\frac{676}{1818}=\\\\=-\frac{2051}{1818}=-1\frac{233}{1818}[/tex]

АDAMiAKviz

[tex]3,5+(2\frac{1}{3}-3,2)^{2}:2,02-5=\frac{7}{2}+(\frac{7}{3}-\frac{16}{5})^{2}:\frac{101}{50}-5=\frac{7}{2}+(\frac{35}{15}-\frac{48}{15})^{2}*\frac{50}{101}-5=\frac{7}{2}+(\frac{13}{15})^{2}*\frac{50}{101}-5=\frac{7}{2}+\frac{169}{225}*\frac{50}{101}-5=\frac{7}{2}+\frac{338}{909}-5=\frac{6363}{1818}+\frac{676}{1818}-5=\frac{7039}{1818}-\frac{9090}{1818}=-\frac{2051}{1818}=-1\frac{233}{1818}[/tex]

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