Odpowiedź:
[tex]\dfrac{20^5\cdot(0,1)^{-2}}{(5^{-1})^{-9}\cdot(\frac{1}{2})^{-11}}=\dfrac{4^5\cdot5^5\cdot(\frac{1}{10})^{-2}}{5^9\cdot2^{11}}=\dfrac{(2^2)^5\cdot5^5\cdot10^2}{5^9\cdot2^{11}}=\dfrac{2^1^0\cdot5^5\cdot5^2\cdot2^2}{5^9\cdot2^1^1}=\\\\\\=\dfrac{2^1^2\cdot5^7}{5^9\cdot2^{11}}=\dfrac{2^{12-11}}{5^{9-7}}=\dfrac{2^1}{5^2}=\dfrac{2}{25}[/tex]
