Rozwiązane

napisz konfiguracje elektronowa podpowlokową jonow pierwiastkow: Ag, Ni i Kr

Odpowiedź :

Wanesabitner77viz

O to chodzi?

[1H] = 1s1

[2He] = 1s2

[3Li] = 1s2 2s1 = [2He] 2s1

[4Be] = 1s2 2s2 = [2He] 2s2

[5B] = 1s2 2s2 2p1 = [2He] 2s2 2p1

[6C] = 1s2 2s2 2p2 = [2He] 2s2 2p2

[7N] = 1s2 2s2 2p3 = [2He] 2s2 2p3

[8O] = 1s2 2s2 2p4 = [2He] 2s2 2p4

ad

[9F] = 1s2 2s2 2p5 = [2He] 2s2 2p5

[10Ne] = 1s2 2s2 2p6

[11Na] = 1s2 2s2 2p6 3s1 = [10Ne] 3s1

[12Mg] = 1s2 2s2 2p6 3s2 = [10Ne] 3s2

[13Al] = 1s2 2s2 2p6 3s2 3p1 = [10Ne] 3s2 3p1

[14Si] = 1s2 2s2 2p6 3s2 3p2 = [10Ne] 3s2 3p2

[15P] = 1s2 2s2 2p6 3s2 3p3 = [10Ne] 3s2 3p3

[16S] = 1s2 2s2 2p6 3s2 3p4 = [10Ne] 3s2 3p4

[17Cl] = 1s2 2s2 2p6 3s2 3p5 = [10Ne] 3s2 3p5

[18Ar] = 1s2 2s2 2p6 3s2 3p6

[19K] = 1s2 2s2 2p6 3s2 3p6 4s1 = [18Ar] 4s1

[20Ca] = 1s2 2s2 2p6 3s2 3p6 4s2 = [18Ar] 4s2

[21Sc] = 1s2 2s2 2p6 3s2 3p6 4s2 3d1 = [18Ar] 3d1 4s2

[22Ti] = 1s2 2s2 2p6 3s2 3p6 4s2 3d2 = [18Ar] 3d2 4s2

[23V] = 1s2 2s2 2p6 3s2 3p6 4s2 3d3 = [18Ar] 3d3 4s2

[24Cr] = 1s2 2s2 2p6 3s2 3p6 4s1 3d5 = [18Ar] 3d5 4s1 (!promocja elektronu)

[25Mn] = 1s2 2s2 2p6 3s2 3p6 4s2 3d5 = [18Ar] 3d5 4s2

[26Fe] = 1s2 2s2 2p6 3s2 3p6 4s2 3d6 = [18Ar] 3d6 4s2

[27Co] = 1s2 2s2 2p6 3s2 3p6 4s2 3d7 = [18Ar] 3d7 4s2

[28Ni] = 1s2 2s2 2p6 3s2 3p6 4s2 3d8 = [18Ar] 3d8 4s2

[29Cu] = 1s2 2s2 2p6 3s2 3p6 4s1 3d10 = [18Ar] 3d10 4s1 (!promocja elektronu)

[30Zn] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 = [18Ar] 3d10 4s2

[31Ga] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1 = [18Ar] 3d10 4s2 4p1

[32Ge] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2 = [18Ar] 3d10 4s2 4p2

…..

[54Xe] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6

[57La] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 5d1 = [54Xe] 5d1 6s2

[58Ce] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f2 = [54Xe] 4f2 6s2

[59Pr] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f3 = [54Xe] 4f3 6s2

[60Nd] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f4 = [54Xe] 4f4 6s2

[61Pm] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f5 = [54Xe] 4f5 6s2

…

[63Eu] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f7 = [54Xe] 4f7 6s2

[64Gd] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f7 5d1 = [54Xe] 4f7 5d1 6s2 (!promocja elektronu)

[65Tb] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f9 = [54Xe] 4f9 6s2

….

Mirael81viz

Odpowiedź:

Ag+  (47)      K2 L8 M18 N18

                     1s22s22p63s23p63d104s24p64d10

Ni+2  (+28)   K2 L8 M16 N2

                    1s2 2s22p6 3s22p63d8  

Krypton jest gazem szlachetnym ,ma wszystkie powłoki zapelnione elektronami

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