Odpowiedź:
[tex]a) (3k-2)(k-4) = 3k^2 -12k-2k+8 = 3k^2-14k+8\\\\b) (2m-1)(m+1)=2m^2+2m-m-1=2m^2+m-1\\\\c)(bc+1)(c-1)=bc^2-bc+c-1\\\\d)(2x-1)(x-2)=2x^2-4x-x+2=2x^2-5x+2\\\\e)(y-4+6)(x+3y)= xy+3y^2-4x-12y+6x+18y=xy+3y^2+2x+6y[/tex]
