d) [tex]\frac{4x-5}{3} - \frac{x+4}{2} = \frac{2(4x-5)-3(x+4)}{6} = \frac{8x-10-3x-12}{6} = \frac{5x-22}{6}[/tex]
g) [tex]\frac{7k+21}{14} - \frac{3k-9}{6} = \frac{7(k+3)}{14} - \frac{3(k-3)}{6} = \frac{k+3}{2} - \frac{k-3}{2} = \frac{k+3-(k-3)}{2} = \frac{k+3-k+3}{2} = \frac{6}{2} = 3[/tex]
