Odpowiedź :
Obliczenia
[tex]a_n=3n-2\\\\a_1=3\cdot1-2=3-2=\boxed1\\\\a_2=3\cdot2-2=6-2=\boxed4\\\\a_3=3\cdot3-2=9-2=\boxed7\\\\a_4=3\cdot4-2=12-2=\boxed{10}\\\\a_5=3\cdot5-2=15-2=\boxed{13}[/tex]
Odpowiedź:
[tex]a_{1} = 1[/tex]
[tex]a_{2} = 4[/tex]
[tex]a_{3} =7[/tex]
[tex]a_{4} = 10[/tex]
[tex]a_{5} = 13[/tex]
Szczegółowe wyjaśnienie:
an=3n-2
[tex]a_{1} = 3 *1 - 2 = 3 - 2 = 1[/tex]
[tex]a_{2} = 3 *2 - 2 = 6 - 2 = 4[/tex]
[tex]a_{3} = 3 *3 - 2 = 9 - 2 = 7[/tex]
[tex]a_{4} = 3 *4 - 2 = 12 - 2 = 10[/tex]
[tex]a_{5} = 3 *5 - 2 = 15 - 2 = 13[/tex]