Obliczenia
[tex]\lim_{x\to3}\frac{2}{x^2}=\frac{2}{3^2}=\frac{2}{9}\\\\\lim_{x\to1}\frac{x^2+2x-4}{x-3}=\frac{1^2+2\cdot1-4}{1-3}=\frac{1+2-4}{-2}=\frac{-1}{-2}=\frac{1}{2}[/tex]
