Szczegółowe wyjaśnienie:
a)
w(x) = 2x³+x²-x = x(2x²+x-1) = *
2x²+x-1 =0
∆= 1-4*2*(-1) = 1+8=9
√∆= 3
x1 = (-1-3)/4 =-4/4 = -1
x2 =(-1+3)/4 =2/4 = 1/2
* w(x) = x (x +1)(x -1/2)
-------------------------------
b)
w(x) =x⁴-2x³+8x² = x²(x²-2x+8) = *
x²-2x+8 =0
∆= = 4-4*1*8 =4-32 = -28 <0
brak pierwiastków
* w(x) = x²(x²-2x+8)
