oblicz napisz działania tylko na ułamkach zwykłych wszystko​

Oblicz Napisz Działania Tylko Na Ułamkach Zwykłych Wszystko class=

Odpowiedź :

1)

[tex]3\frac{1}{4}+2,5=3\frac{25}{100}+2,5=3,25+2,5=5,75\\[/tex]

2)

[tex]4,9-1\frac{3}{5}=4,9-1\frac{6}{10}=4,9-1,6=3,3\\[/tex]

3)

[tex]8,25-4\frac{1}{2}=8,25-4\frac{5}{10}=8,25-4,5=3,75\\[/tex]

4)

[tex]4\frac{1}{8}+5,45=4\frac{125}{1000}+5,45=4,125+5,45=9,565\\[/tex]

5)

[tex]3\frac{2}{3}+4,25=3\frac{2}{3}+4\frac{25}{100}=3\frac{2}{3}+4\frac{1}{4}=3\frac{8}{12}+4\frac{3}{12}=7\frac{11}{12}\\[/tex]

6)

[tex]6,4-2\frac{1}{9}=6\frac{4}{10}-2\frac{1}{9}=6\frac{2}{5}-2\frac{1}{9}=6\frac{18}{45}-2\frac{5}{45}=4\frac{13}{45}\\[/tex]

7)

[tex]3,5:2\frac{1}{3}=3\frac{5}{10}:\frac{7}{3}=3\frac{1}{2}:\frac{7}{3}=\frac{\not7^1}{2}\cdot\frac{3}{\not7_1}=\frac{3}{2}=1\frac{1}{2}\\[/tex]

8)

[tex]2,4\cdot3\frac{3}{4}=2\frac{2}{5}\cdot\frac{15}{4}=\frac{\not12^3}{\not5_1}\cdot\frac{\not15^3}{\not4_1}=9[/tex]

9)

[tex]2\frac{1}{2}\cdot1,5=\frac{5}{2}\cdot1\frac{1}{2}=\frac{5}{2}\cdot\frac{3}{2}=\frac{15}{4}=3\frac{3}{4}\\[/tex]

10)

[tex]2,125:1\frac{1}{4}=2\frac{125}{1000}:\frac{5}{4}=2\frac{1}{8}\cdot\frac{4}{5}=\frac{17}{\not8_2}\cdot\frac{\not4^1}{5}=\frac{17}{10}=1\frac{7}{10}\\[/tex]

11)

[tex](1,6-\frac{3}{5}+0,25)\cdot2=(1,6-\frac{6}{10}+0,25)\cdot2=\\\\=(1,6-0,6+0,25)\cdot2=(1+0,25)\cdot2=1,25\cdot2=2,5[/tex]

Odpowiedź:

[tex]3\frac{1}{4}+2,5 = 3\frac{1}{4}+2\frac{1}{2}=3\frac{1}{4}+2\frac{2}{4}=5\frac{3}{4}[/tex]

[tex]4,9-1\frac{3}{5}=4\frac{9}{10}-1\frac{6}{10}=3\frac{3}{10}[/tex]

[tex]8,25-4\frac{1}{2}=8\frac{1}{4}-4\frac{2}{4}=7\frac{5}{4}-4\frac{2}{4}=3\frac{3}{4}[/tex]

[tex]4\frac{1}{8}+5,45=4\frac{1}{8}+5\frac{45}{100}=4\frac{1}{8}+5\frac{9}{20}=4\frac{5}{40}+5\frac{18}{40}=9\frac{23}{40}[/tex]

[tex]3\frac{2}{3}+4,25=3\frac{2}{3}+4\frac{1}{4}=3\frac{8}{12}+4\frac{3}{12}=7\frac{11}{12}[/tex]

[tex]6,4-2\frac{1}{9}=6\frac{2}{5}-2\frac{1}{9}=6\frac{18}{45}-2\frac{5}{45}=4\frac{13}{45}[/tex]

[tex]3,5 : 2\frac{1}{3}=3\frac{1}{2}:\frac{7}{3}=\frac{7}{2}*\frac{3}{7}=\frac{3}{2}=1\frac{1}{2}[/tex]

[tex]2,4*3\frac{3}{4}=2\frac{2}{5}*3\frac{3}{4}=\frac{12}{5}*\frac{15}{4}=9[/tex]

[tex]2\frac{1}{2}*1,5=\frac{5}{2}*1\frac{1}{2}=\frac{5}{2}*\frac{3}{2}=\frac{15}{4}=3\frac{3}{4}[/tex]

[tex]2,125 :1\frac{1}{4}=2\frac{1}{8}:\frac{5}{4}=\frac{17}{8}*\frac{4}{5}=\frac{17}{10}=1\frac{7}{10}[/tex]

[tex](1,6-\frac{3}{5}+0,25)*2 = (1\frac{3}{5}-\frac{3}{5}+\frac{1}{4})*2=1\frac{1}{4}*2=\frac{5}{4}*2=\frac{5}{2}=2\frac{1}{2}[/tex]

Szczegółowe wyjaśnienie: