Odpowiedź:
a) [tex]-2x+4\geq x\sqrt{2} \\ -2x-x\sqrt{2}\geq -4\\x(-2-\sqrt{2})\geq -4\\x\geq \frac{-4}{-2-\sqrt{2}} \\x\leq -2(-2+\sqrt{2})\\x\leq 4-2\sqrt{2}[/tex]
b) [tex]6+x\sqrt{7}<3x+2\sqrt{7}\\x\sqrt{7}-3x<2\sqrt{7}-6\\(\sqrt{7}-3)x<2\sqrt{7}-6\\x>\frac{2\sqrt{7}-6}{\sqrt{7}-3}\\x>\frac{2(\sqrt{7}-3)}{\sqrt{7}-3}\\x>2[/tex]
mam nadzieję, że dobrze :)
