Odpowiedź:
[tex]f)\\\\(2x-1)(3x-1)-(3x-2)(2x-3)=0\\\\6x^2-2x-3x+1-(6x^2-9x-4x+6)=0\\\\6x^2-5x+1-(6x^2-13x+6)=0\\\\6x^2-5x+1-6x^2+13x-6=0\\\\8x-5=0\\\\8x=5\ \ /:8\\\\x=\frac{5}{8}[/tex]
[tex]g)\\\\(4-x)(2x+3)+2x^2=6\\\\8x+12-2x^2-3x+2x^2=6\\\\5x+12=6\\\\5x=6-12\\\\5x=-6\ \ /:5\\\\x=-\frac{6}{5}\\\\x=-1\frac{1}{5}\\\\\\h)\\\\(2x+3)(3x-1)+4=(6x-2)(x+1)\\\\6x^2-2x+9x-3+4=6x^2+6x-2x-2\\\\6x^2+7x+1=6x^2+4x-2\\\\6x^2+7x-6x^2-4x=-2-1\\\\3x=-3\ \ /:3\\\\x=-1[/tex]
