-3(2x-y)=
4c-k (3m-2)=
2(z-4x)-4ł=
2x-(5+z)=
6x+(4z-9k)=
2x-(5ł-z)=​


Odpowiedź :

[tex]-3(2x-y)=-3*2x-(-3*y)=-6x-(-3y)=-6x+3y\\\\4c-k(3m-2)=4c-3km+2k\\\\2(z-4x)-4l=2z-8x-4l\\\\2x-(5+z)=2x-5-z\\\\6x+(4z-9k)=6x+4z-9k\\\\2x-(5l-z)=2z-5l+z[/tex]