matematyka!! zadanie w załączniku

Matematyka Zadanie W Załączniku class=

Odpowiedź :

[tex]a)\\\\\frac{ - \frac{2}{3}*(5-6*2\frac{1}{3}) }{3\frac{2}{5}-2,2 :\frac{2}{5}}=\frac{ - \frac{2}{3}*(5-\not{6}^2* \frac{7}{\not{3}^1}) }{ \frac{17}{5}-\frac{\not{22}^{11}}{\not{10}^2}*\frac{\not{5}^1}{\not{2}^1}}=\frac{-\frac{2}{3}*(5-14)}{\frac{17}{5}-\frac{11}{2}}=\frac{-\frac{2}{\not{3}^1}*( -\not{9}^3)}{\frac{17}{5}-\frac{11}{2}} =\\\\=\frac{6}{\frac{34}{10}-\frac{55}{10}} =\frac{6}{-\frac{21}{10}}=6:(-\frac{21}{10})=-\not{6}^2*\frac{10}{\not{21}^7} =\frac{-20}{7}=-2\frac{6}{7}[/tex]