Odpowiedź:
[tex]
( - ( - \frac{1}{2} x + 2 )( 2 - \frac{1}{2} x) + ( 1 + \frac{1}{2} x)²=0 \\ - ( - \frac{1}{2} x + 2 {)}^{2} + 1 + x + \frac{1}{4} {x}^{2} = 0 \\ - ( \frac{1}{4} {x}^{2} - 2x + 4) + 1 + x + \frac{1}{4} {x}^{2} = 0 \\ - \frac{1}{4} {x}^{2} + 2x - 4 + 1 + x + \frac{1}{4} {x}^{2} = 0 \\ 3x - 3 = 0 \\ 3x = 3 \\ x = 1[/tex]
