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Odpowiedź :

SoeCruviz

[tex]7\sqrt{3} -5\sqrt{3} =2\sqrt{3}[/tex]

[tex]\sqrt{56} \cdot\sqrt{3\frac{1}{2} } =\sqrt{56} \cdot\sqrt{\frac{7}{2} } =\sqrt{28\cdot7} =\sqrt{196} =14[/tex]

[tex]\sqrt{500} +2\sqrt{5} =\sqrt{2\cdot2\cdot5\cdot5\cdot5} +2\sqrt{5} =2\cdot5\sqrt{5} +2\sqrt{5} =10\sqrt{5} +2\sqrt{5} =12\sqrt{5}[/tex]

[tex]7\sqrt{35} \cdot\frac{1}{5} \sqrt{5} =\frac{7\sqrt{35\cdot5} }{5} =\frac{7\sqrt{175} }{5} =\frac{7\cdot5\sqrt{7} }{5} =\frac{\not35\sqrt{7} }{\not5} =7\sqrt{7}[/tex]

[tex](\frac{2\sqrt{21} }{3} )^2=\frac{(2\sqrt{21} )^2}{3^2} =\frac{4\cdot21}{3\cdot3} =\frac{84}{9} =\frac{28}{3} =9\frac{1}{3}[/tex]

Magdaviz

Odpowiedź:

[tex]a)\ \ 7\sqrt{3}-5\sqrt{3}=(7-5)\sqrt{3}=2\sqrt{3}\\\\\\b)\ \ \sqrt{56}\cdot\sqrt{3\frac{1}{2}}=\sqrt{56\cdot3\frac{1}{2}}=\sqrt{\not56^2^8\cdot\frac{7}{\not2_{1}}}=\sqrt{28\cdot7}=\sqrt{196}=14\\\\\\c)\ \ \sqrt{500}+2\sqrt{5}=\sqrt{100\cdot5}+2\sqrt{5}=10\sqrt{5}+2\sqrt{5}=12\sqrt{5}\\\\\\d)\ \ 7\sqrt{35}\cdot\frac{1}{5}\sqrt{5}=\frac{7}{5}\sqrt{35\cdot5}=\frac{7}{5}\sqrt{175}=\frac{7}{5}\sqrt{25\cdot7}=\frac{7}{\not5}\cdot\not5\sqrt{7}=7\sqrt{7}[/tex]

[tex]e)\ \ \left(\dfrac{2\sqrt{21}}{3}\right)^2=\dfrac{2^2\cdot(\sqrt{21})^2}{3^2}=\dfrac{4\cdot21}{9}=\dfrac{84}{9}=\dfrac{28}{3}=9\dfrac{1}{3}[/tex]

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