Odpowiedź:
logₐb Df: a > 0 i a ≠ 1 ; b > 0
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a)
f(x) = log₃x ; Df: < 1/3 , 1 >
log₃1/3 = - 1
log₃1 = 0
ZWf: y ∈ < - 1 , 0 >
b)
f(x) = log₁₎₃x ; Df: < 1/9 , 27 >
log₁₎₃1/9 = 2
log₁₎₃27 = - 3
ZWf: y ∈ < - 3 , 2 >
c)
f(x) = log₁₎₄x ; Df: < 1/2 , 8 >
log₁₎₄1/2 = 1/2
log₁₎₄8 = - 3/2 = - 1,5
ZWf: y ∈ < - 1,5 ; 1/2 >
d)
f(x) = log₈x ; Df: < 1/2 , √2 >
log₈1/2 = - 1/3
log₈√2 = 1/6
ZWf: y ∈ < - 1/3 , 1/6 >
