d)
[tex]5-\frac{4-x}{4}=\frac{3+2,5x}{2} \ \ /\cdot4\\\\20-(4-x)=2(3+2,5x)\\\\20-4+x=6+5x\\\\x-5x=6-20+4\\\\-4x=-10 \ \ /:(-4)\\\\\huge\boxed{x=2,5}[/tex]
f)
[tex]\frac{5x-11}{0,4}-(x-1)=\frac{11x-1}{1,2} \ \ /\cdot1,2\\\\3(5x-11)-1,2(x-1)=11x-1\\\\15x-33-1,2x+1,2=11x-1\\\\15x-1,2x-11x=-1+33-1,2\\\\2,8x=30,8 \ \ /:2,8\\\\\huge\boxed{x=11}[/tex]
