Odpowiedź:
Szczegółowe wyjaśnienie:
a)
(64 * 12)/(3³ * 3^4) = (2^6 * 3 * 2²)/(3^7) = (2^8)/(3^6) = 4 * (2/3)^6
b)
(x^36 : x^60)/(x^16) - x^40 : x^18 + (-x^75)^0 = x^(36-60-16) - x^(40-18) + 1 =
= x^(-40) - x^22 + 1 = 1/(x^40) - x^22 + 1
c) (2^7 + 2^5)/5 = 2^5 * (2² + 1)/5 = 2^5 *(5)/5 = 2^5 = 32