[tex]log(x+2) = 2\\\\Z:\\x+2 >0\\x > -2\\\\log_{a}b = c, \ \ to \ \ a^{c} = b\\\\log(x+2) = 2\\\\log_{10}(x+2) = 2\\\\10^{2} = x+2\\\\100 = x+2\\\\\underline{x = 98}[/tex]
