Odpowiedź i szczegółowe wyjaśnienie:
[tex]ZADANIE\ 5.\\\\\dfrac{2}{\sqrt{11}}=\dfrac{2}{\sqrt{11}}\cdot\dfrac{\sqrt{11}}{\sqrt{11}}=\dfrac{2\sqrt{11}}{11}\\\\\\\dfrac{4}{5\sqrt2}=\dfrac{4}{5\sqrt2}\cdot\dfrac{5\sqrt2}{5\sqrt2}=\dfrac{20\sqrt2}{5\cdot2}=\dfrac{20\sqrt2}{10}=2\sqrt2\\\\\\\dfrac{4\sqrt2}{\sqrt5}=\dfrac{4\sqrt2}{\sqrt5}\cdot\dfrac{\sqrt5}{\sqrt5}=\dfrac{4\sqrt{10}}{5}[/tex]
ZADANIE 6.
[tex]a)\ 2\sqrt{50}-3\sqrt{32}=2\sqrt{25\cdot2}-3\sqrt{16\cdot2}=2\cdot5\sqrt2-3\cdot4\sqrt2=\\\\=10\sqrt2-12\sqrt2=-2\sqrt2\\\\\\b)\ 3\sqrt{75}-2\sqrt3=3\sqrt{25\cdot3}-2\sqrt3=3\cdot5\sqrt3-2\sqrt3=15\sqrt3-2\sqrt3=12\sqrt3[/tex]
