Odpowiedź:
[tex]\dfrac{-3,6\cdot\frac{2}{3}-0,8\cdot(-\frac{3}{4})^2}{-0,6\cdot\frac{5}{6}+(-\frac{1}{2})}=\dfrac{-\frac{\not36^1^2}{\not10_{5}}\cdot\frac{\not2^1}{\not3_{1}}-\frac{\not8^1}{10}\cdot\frac{9}{\not16_{2}}}{-\frac{\not6^1}{\not10_{2}}\cdot\frac{\not5^1}{\not6_{1}}-\frac{1}{2}}=\dfrac{-\frac{12}{5}-\frac{9}{20}}{-\frac{1}{2}-\frac{1}{2}}=\dfrac{-\frac{48}{20}-\frac{9}{20}}{-1}=\\\\\\=\dfrac{-\frac{57}{20}}{-1}=\frac{57}{20}=2\frac{17}{20}[/tex]
