[tex]dane:\\m = 12 \ kg\\p = 550 \ Pa = 550 \ \frac{N}{m^{2}}\\g = 10\frac{N}{kg}\\szukane:\\S = ?\\\\\\p = \frac{F}{S} \ \ \rightarrow \ \ S = \frac{F}{p}\\\\F = m\cdot g = 12 \ kg\cdot10\frac{N}{kg} = 120 \ N\\\\S = \frac{120 \ N}{550\frac{N}{m^{2}}}=0,2(18) \ m^{2}\approx0,22 \ m^{2}[/tex]
Odp. Powierzchnia podstawy paczki S ≈ 0,22 m².
