Odpowiedź:
a) [tex]2\sqrt{2}=\sqrt{2^{2}*2 }=\sqrt{4*2}=\sqrt{8}[/tex]
b) [tex]4\sqrt[3]{3} =\sqrt[3]{4^{3}*3 }=\sqrt[3]{64*3}=\sqrt[3]{192}[/tex]
c) [tex]6\sqrt{2}=\sqrt{6^{2}*2 }=\sqrt{36*2}=\sqrt{72}[/tex]
d) [tex]20\sqrt[3]{0,1}=\sqrt[3]{20^{3}*0,1 }=\sqrt[3]{8000*0,1}=\sqrt[3]{800}[/tex]
e) [tex]5\sqrt{11}=\sqrt{5^{2}*11 } =\sqrt{25*11} =\sqrt{275}[/tex]
f) [tex]-10\sqrt[3]{0,01} =\sqrt[3]{(-10)^{3}*0,01 }=\sqrt[3]{-1000*0,01}=\sqrt[3]{-10}[/tex]
g) [tex]0,2\sqrt{30}=\sqrt{0,2^{2}*30 }=\sqrt{0,04*30} =\sqrt{1,2}[/tex]
h) [tex]\frac{1}{4} \sqrt[3]{4} =\sqrt[3]{\frac{1}{4} ^{3}*4 } =\sqrt[3]{\frac{1}{64}*4 }=\sqrt[3]{\frac{1}{16} }[/tex]
Szczegółowe wyjaśnienie:
