Odpowiedź:
[tex](2,5-1\frac{1}{4}+\frac{2}{3}):3\frac{5}{6}\cdot\frac{6}{5}=(2\frac{1}{2}-1\frac{1}{4}+\frac{2}{3}):\frac{23}{6}\cdot\frac{6}{5}=(2\frac{6}{12}-1\frac{3}{12}+\frac{8}{12})\cdot\frac{6}{23}\cdot\frac{6}{5}=\\\\=1\frac{11}{12}\cdot\frac{6}{23}\cdot\frac{6}{5}=\frac{\not23^1}{\not12_{2}}\cdot\frac{\not6^1}{\not23_{1}}\cdot\frac{6}{5}=\frac{1}{\not2_{1}}\cdot\frac{\not6^3}{5}=\frac{3}{5}[/tex]
