Witam potrzebna pomoc w zadaniu daje 100 pkt.
(2a+6)(3a+5)=
(3p-2)(5p+4)=
(2x-3)(5x-1)=
(3y-2)(4-3y)=
x(3x+6)+(x-4)(2x+1)=
2a(5a-3)-(2a+3)(a+4)=
(3u-2)(2u-1)-5u(2u+3)=