Obliczenia
[tex]\frac{3-2\sqrt3}{4\sqrt3}=\frac{3-2\sqrt3}{4\sqrt3}\cdot\frac{\sqrt3}{\sqrt3}=\frac{3\sqrt3-2\sqrt{3^2}}{4\sqrt{3^2}}=\frac{3\sqrt3-2\cdot3}{4\cdot3}=\frac{3\sqrt3-6}{12}=\frac{\sqrt3-2}{4}\\\\gotowe![/tex]
