[tex]dane:\\m = 158 \ g \\V = 0,02\ dm^{3} = 0,02\cdot1000 \ cm^{3}= 20 \ cm^{3}\\szukane:\\d = ?\\\\d = \frac{m}{V}\\\\d = \frac{158 \ g}{20 \ cm^{3}}\\\\\underline{d = 7,9\frac{g}{cm^{3}}=7900\frac{kg}{m^{3}}}[/tex]
Odp. Gęstość tej kulki d = 7,9 g/cm³ (7900 kg/m³).
