Obliczenia do a)
[tex]\frac{3}{5}+\frac{7}{10}=\frac{6}{10}+\frac{7}{10}=\frac{13}{10}=1\frac{3}{10}\\\\\frac{4}{15}-\frac{4}{15}=0\\\\\frac{11}{30}+\frac{1}{6}=\frac{11}{30}+\frac{5}{30}=\frac{16}{30}=\frac{8}{15}[/tex]
Obliczenia do b)
[tex]2\frac{9}{16}-1\frac{1}{4}=2\frac{9}{16}-1\frac{4}{16}=1\frac{5}{16}\\\\12\frac{2}{3}+1\frac{3}{4}=12\frac{8}{12}+1\frac{9}{12}=13\frac{17}{12}=14\frac{5}{12}\\\\8\frac{1}{8}-\frac{2}{3}=8\frac{3}{24}-\frac{16}{24}=7\frac{27}{24}-\frac{16}{24}=7\frac{11}{24}[/tex]
Obliczenia do c)
[tex]6\frac{1}{4}-3\frac{5}{6}=6\frac{3}{12}-3\frac{10}{12}=5\frac{15}{12}-3\frac{10}{12}=2\frac{5}{12}\\\\7\frac{1}{6}+6\frac{1}{8}=7\frac{4}{24}+6\frac{3}{24}=13\frac{7}{24}\\\\6\frac{1}{3}-3\frac{5}{6}=6\frac{2}{6}-3\frac{5}{6}=5\frac{8}{6}-3\frac{5}{6}=2\frac{3}{6}=2\frac{1}{2}[/tex]
