Odpowiedź:
[tex](1\frac{1}{5})^{-2}:0,3=(\frac{6}{5})^{-2}:\frac{3}{10}=(\frac{5}{6})^2:\frac{3}{10}=\frac{25}{\not36_{18}}\cdot\frac{\not10^5}{3}=\frac{125}{54}=2\frac{17}{54}\\\\\\(2^{-3})^{-4}:2^6=2^{-3\cdot(-4)}:2^6=2^{12}:2^6=2^{12-6}=2^6=64\\\\\\\dfrac{3^6}{3^4}=3^{6-4}=3^2=9[/tex]
