Odpowiedź:
zad9
a) [tex]6^{-3}}*6^5=6^{-3+5}}=6^2=36[/tex]
b)[tex]4^{-8}}*5^6=4^{-8+6}}=4^{-2}}=(\frac{1}{4} )^2=\frac{1}{16}[/tex]
c)[tex]0,5^{-4}}*0,5^{-1}}=0,5^{-4+(-1)}}=(\frac{5}{10} )^{-5}}=(\frac{1}{2} )^{-5}}=2^5=32[/tex]
d)[tex](\frac{2}{3} )^2*(\frac{2}{3})^{-5}}=(\frac{2}{3})^{2-5}}=(\frac{2}{3})^{-3}}=(\frac{3}{2} )^3=\frac{27}{8} =3\frac{3}{8}[/tex]
e)[tex]5^7:5^{10}}=5^{7-10}}=5^{-3}}=(\frac{1}{5})^3=\frac{1}{125}[/tex]
f)[tex]7^{-4}}:7^{-6}}=7^{-4-(-6)}}=7^2=49[/tex]
g)[tex](\frac{3}{4} ):(\frac{3}{4})^{-3}}=(\frac{3}{4})^ {-5-(-3)}}=(\frac{3}{4} )^{-2}}=(\frac{4}{3})^2=\frac{16}{9}=1\frac{7}{9}[/tex]
h)[tex](\frac{3}{8} )^7:(\frac{3}{8})^8=(\frac{3}{8} )^{7-8}}=(\frac{3}{8} )^{-1}}=\frac{8}{3} =2\frac{2}{3}[/tex]
i)(3⁶)⁻²*3¹⁰=3⁻¹²⁺¹⁰=3⁻²=(1/3)²=1/9
j)(6⁻²)⁵*6⁸=6⁻¹⁰⁺⁸=6⁻²=(1/6)²=1/36
k)(4⁻³)⁻⁴:4⁹=4¹²⁻⁹=4³=64
l)(8⁴)⁻²:8⁻¹⁰=8⁻⁸⁻⁽⁻¹⁰⁾=8²=64
Szczegółowe wyjaśnienie:
