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Basetlaviz Basetlaviz · Answer 1

a)

[tex]0^{2} = 0\cdot0 = 0\\\\2^{2} = 2\cdot 2 = 4\\\\11^{2} = 11\cdot11 = 121\\\\4^{2} = 4\cdot4 = 16[/tex]

b)

[tex]6^{2} = 6\cdot6 = 36\\\\7^{2} = 7\cdot7 = 49\\\\8^{2} = 8\cdot8 = 64\\\\9^{2} = 9\cdot9 = 81[/tex]

c)

[tex]2^{3} = 2\cdot2\cdot2 = 8\\\\1^{5} = 1\cdot1\cdot1\cdot1\cdot1 = 1\\\\5^{3} = 5\cdot5\cdot5 = 125\\\\3^{3} = 3\cdot3\cdot3 = 27[/tex]

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MertBviz MertBviz · Answer 2

Cześć!

Ćwiczenie 4.

Szczegółowe wyjaśnienie:

a)

[tex]0^{2} =0\cdot0=\boxed0\\2^{2} =2\cdot2=\boxed4\\11^{2} = 11\cdot 11 = \boxed{121}\\4^{2} =4\cdot4=\boxed{16}[/tex]

b)

[tex]6^{2} =6\cdot6=\boxed{36}\\7^{2} =7\cdot7=\boxed{49}\\8^{2} =8\cdot8=\boxed{64}\\9^{2}=9\cdot9=\boxed{81}[/tex]

c)

[tex]2^{3} =2\cdot2\cdot2=\boxed8\\1^{5} =1\cdot1\cdot1\cdot1\cdot1=\boxed1\\5^{3}= 5\cdot5\cdot5=\boxed{125}\\3^{3} =3\cdot3\cdot3=\boxed{27}[/tex]