[tex]zad.e\\\\1\frac{1}{5}\cdot 1\frac{2}{3} +(1\frac{1}{7} )^{2} =\frac{6}{5} \cdot \frac{5}{3} +(\frac{8}{7} )^{2} =2+\frac{64}{49} =2+1\frac{15}{49}=3 \frac{15}{49}\\\\zad.f\\\\(2\frac{1}{6} -\frac{2}{3} )^{2} -2\frac{1}{5} =(\frac{13}{6} -\frac{4}{6} )^{2} -2\frac{1}{5}=(\frac{9}{6} )^{2} -2\frac{1}{5} =(\frac{3}{2} )^{2} -2\frac{1}{5}=\frac{9}{4} -2\frac{1}{5} =2\frac{1}{4} -2\frac{1}{5} =2\frac{5}{20} -2\frac{4}{20} =\frac{1}{20} =0,05[/tex]
[tex]zad.g\\\\10-2\cdot(3\frac{1}{5} -2\frac{1}{4} \cdot\frac{1}{3} )=10-2\cdot(3\frac{1}{5} -\frac{9}{4} \cdot\frac{1}{3} )=10-2\cdot(3\frac{1}{5} -\frac{3}{4} )=10-2\cdot(3\frac{4}{20} -\frac{15}{20} )=10-2\cdot(\frac{64}{20} -\frac{15}{20} )=10-2\cdot \frac{49}{20} =10-\frac{49}{10} =10-4\frac{9}{10}=9\frac{10}{10} -4\frac{9}{10} =5\frac{1}{10} =5,1[/tex]
[tex]zad.h\\\\(\frac{7}{3} -\frac{5}{12} +1\frac{1}{2}) \div (2\frac{3}{4} -\frac{5}{6} )=(\frac{56}{24} -\frac{10}{24} +1\frac{12}{24}) \div (2\frac{9}{12} -\frac{10}{12} )=(\frac{46}{24} +\frac{36}{24})\div (\frac{33}{12} -\frac{10}{12} )=\frac{10}{24} \div \frac{23}{12} =\frac{10}{24} \cdot \frac{12}{23} =\frac{10}{46} =\frac{5}{23}[/tex]
