Odpowiedź:
[tex]1\frac{3}{4}*1\frac{1}{7}-3:4\frac{1}{2}=\frac{7}{4}*\frac{8}{7}-3:\frac{9}{2}=2-3*\frac{2}{9}=2-\frac{2}{3}=1\frac{1}{3}[/tex]
[tex]1\frac{5}{7}*(2\frac{3}{4}-1\frac{2}{3}:4)=1\frac{5}{7}*(2\frac{3}{4}-\frac{5}{3}*\frac{1}{4})=1\frac{5}{7}*(2\frac{3}{4}-\frac{5}{12})= 1\frac{5}{7}*(2\frac{9}{12}-\frac{5}{12} )=1\frac{5}{7}*2\frac{4}{12}=\frac{12}{7}* \frac{28}{12}=4[/tex]
[tex]3\frac{1}{3}*(2\frac{1}{4}-1\frac{1}{2}:5)=3\frac{1}{3}*(2\frac{1}{4}-\frac{3}{2}*\frac{1}{5} )=3\frac{1}{3}*(2\frac{1}{4}-\frac{3}{10})=3\frac{1}{3}*(2\frac{5}{20}-\frac{6}{20} )=3\frac{1}{3}*(1\frac{25}{20}-\frac{6}{20} )=3\frac{1}{3}*1\frac{19}{20}=\frac{10}{3}*\frac{39}{20}=\frac{13}{2}=6\frac{1}{2}[/tex]
[tex]\frac{3\frac{1}{4}+\frac{1}{2} }{3\frac{1}{3}*(1\frac{5}{6}-1\frac{1}{12}) }=\frac{3\frac{1}{4} +\frac{2}{4} }{3\frac{1}{3}*(1\frac{10}{12}-1\frac{1}{12}) }=\frac{3\frac{3}{4} }{3\frac{1}{3}*\frac{3}{4} }=\frac{3\frac{3}{4} }{\frac{10}{3}*\frac{3}{4} }=3\frac{3}{4} :\frac{5}{2}=\frac{15}{4}*\frac{2}{5}=\frac{3}{2}=1\frac{1}{2}[/tex]
Szczegółowe wyjaśnienie:
