Odpowiedź:
W(y) = x³ - 4x² + x + 6
Schemat Hornera
1 (- 4) 1 6
3 3 (- 3) (- 6)
1 (- 1) (- 2) 0
x³ - 4x² + x + 6 = (x² - x - 2)(x - 3)
(x² - x - 2)(x - 3) = 0
x² - x - 2 = 0 ∨ x - 3 = 0
x² - x - 2 = 0
a = 1 , b = - 1 , c = - 2
Δ = b² - 4ac = (- 1)² - 4 * 1 * (- 2) = 1 + 8 = 9
√Δ = √9 = 3
x₁ = ( - b - √Δ)/2a = ( 1 - 3)/2 = - 2/2 = - 1
x₂ = (- b + √Δ)/2a = (1 + 3)/2 = 2
x = - 1 , x = 2 , x - 3 = 0
x = - 1 , x = 2 , x = 3
