Zad. 7 OBLICZ
C)
[tex] \frac{42}{81} \times \frac{9}{14} = [/tex]
F)
[tex]6 \times 2 \times \frac{2}{3} = [/tex]

I)
[tex]4 \frac{1}{6} \times 1 \frac{11}{25} [/tex]
L)
[tex]1 \frac{5}{13} \times 2 \frac{8}9 \times 4 \frac{3}{4} = [/tex]
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Odpowiedź :

[tex]\frac{42}{81}*\frac{9}{14}=\frac{42}{9}*\frac{1}{14}=\frac{3}{9}*\frac{1}{1}=\frac{3}{9}=\frac{1}{3}[/tex]

[tex]6*2*\frac{2}{3}=12*\frac{2}{3}=\frac{12}{1}*\frac{2}{3}=\frac{4}{1}*\frac{2}{1}=8[/tex]

[tex]4\frac{1}{6}*1\frac{11}{25}=\frac{25}{6}*\frac{36}{25}=\frac{1}{6}*\frac{36}{1}=\frac{1}{1}*\frac{6}{1}=\frac{6}{1}=6[/tex]

[tex]1\frac{5}{13}*2\frac{8}{9}*4\frac{3}{4}=\frac{18}{13}*\frac{26}{9}*\frac{19}{4}=\frac{2}{13}*\frac{26}{1}*\frac{19}{4}=\frac{2}{1}*\frac{2}{1}*\frac{19}{4}=\frac{4}{1}*\frac{19}{4}=\frac{19}{1}=19[/tex]