Cześć ;-)
Obliczenia
[tex][(-\frac{2}{3})^2:\frac{8}{9}]^2-(\frac{3}{4}-1\frac{1}{8})=(\frac{4}{9}:\frac{8}{9})-(\frac{6}{8}-\frac{9}{8})=\\\\=\frac{4}{9}\cdot\frac{9}{8}-(-\frac{3}{8})=\frac{1}{2}+\frac{3}{8}=\frac{4}{8}+\frac{3}{8}=\frac{7}{8}[/tex]
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