Hej potrzebuje Tego zadania tylko że F G H help me!!!!!! Mam to na jutro

[tex](2\frac{1}{6} -\frac{2}{3} )^{2} -2\frac{1}{5} =(\frac{13}{6} -\frac{2}{3})^{2} -\frac{11}{5} =(\frac{13}{6} -\frac{4}{6})^{2} -\frac{11}{5}=(\frac{9}{6} )^{2} -\frac{11}{5}=(\frac{3}{2}) ^{2} -\frac{11}{5}=\frac{9}{4} -\frac{11}{5}=\frac{45}{20} -\frac{44}{20} = \frac{1}{20}[/tex]

g)

[tex]10-2*(3\frac{1}{5} -2\frac{1}{4} *\frac{1}{3} )=10-2*(\frac{16}{5} -\frac{9}{4} *\frac{1}{3} )=10-2*(\frac{16}{5} -\frac{9}{12} )=10-2*(\frac{192}{60} -\frac{45}{60})=10-2*\frac{147}{60}=\frac{600}{60}-\frac{294}{60} =\frac{306}{60} =\frac{51}{10} =5\frac{1}{10}[/tex]

h)

[tex](\frac{7}{3} -\frac{5}{12} +1\frac{1}{2} ):(2\frac{3}{4} -\frac{5}{6} )=(\frac{28}{12} -\frac{5}{12} +\frac{18}{12} ):(\frac{33}{12} -\frac{10}{12} )=\frac{41}{12} :\frac{23}{12} =\frac{41}{12} *\frac{12}{23}=\frac{41}{23} =1\frac{18}{23}[/tex]

Gosiagrazaviz Gosiagrazaviz · Answer 2

Odpowiedź:

(2 i 1/6 - 2/3)² - 2 i 1/5 = (2 i 1/6 - 4/6)² - 2 i 1/5 = (1 i 7/6 - 4/6)² - 2 i 1/5 = (1 i 3/6)² - 2 i 1/5 = 81/36 - 2 i 1/5 = 2 i 9/36 - 2 i 1/5 = 2 i 45/180 - 2 i 36/180 = 9/180 = 1/20

10 - 2 * (3 i 1/5 - 2 i 1/4 * 1/3) = 10 - 2 * (3 i 1/5 - 9/4 * 1/3) = 10 - 2 * (3 i 1/5 - 3/4) = 10 - 2 * (3 i 4/20 - 15/20) = 10 - 2 * (64/20 - 15/20) = 10 - 2 * 49/20 = 10 - 49/10 = 10 - 4 i 9/10 = 9 i 10/10 - 4 i 9/10 = 5 i 1/10

(7/3 - 5/12 + 1 i 1/2) : (2 i 3/4 - 5/6) = (28/12 - 5/12 + 1 i 6/12) : (2 i 9/12 - 10/12) = (23/12 + 1 i 6/12) : (1 i 21/12 - 10/12) = 1 i 29/12 : 1 i 11/12 = 41/12 : 23/12 = 41/12 * 12/23 = 41/23 = 1 i 18/23