metoda kzyrxowa pls
a)
[tex] \frac{15}{16} = \frac{x}{18} [/tex]
b)
[tex] \frac{z}{20} = \frac{4}{7} [/tex]
c)
[tex] \frac{3}{x} = \frac{4}{5} [/tex]
d)
[tex] \frac{1.6}{x } = \frac{2}{5} [/tex]


Odpowiedź :

Odpowiedź:

[tex]a)\\\\\frac{15}{16}=\frac{x}{18}\\\\270=16x\\\\16x=270\ \ /:16\\\\x=\frac{270}{16}\\\\x=\frac{135}{8}\\\\x=16\frac{7}{8}\\\\\\b)\\\\\frac{z}{20}=\frac{4}{7}\\\\7z=80\ \ /:7\\\\z=\frac{80}{7}\\\\z=11\frac{3}{7}[/tex]

[tex]c)\\\\\frac{3}{x}=\frac{4}{5}\ \ \ \ \ \ x\neq 0\\\\15=4x\\\\4x=15\ \ /:4\\\\x=\frac{15}{4}\\\\x=3\frac{3}{4}\\\\\\d)\\\\\frac{1,6}{x}=\frac{2}{5}\ \ \ \ \ \ x\neq 0\\\\8=2x\\\\2x=8\ \ /:2\\\\x=4[/tex]