Cześć ;-)
a)
[tex](1\frac{4}{5}-3\frac{2}{7})\cdot5\frac{5}{13}=(\frac{9}{5}-\frac{23}{7})\cdot\frac{70}{13}=\\\\=(\frac{63}{35}-\frac{115}{35})\cdot\frac{70}{13}=-\frac{\not52^4}{\not35_1}\cdot\frac{\not70^2}{\not13_1}=-4\cdot2=-8[/tex]
b)
[tex]1\frac{4}{5}-3\frac{2}{7}\cdot5\frac{5}{13}=1\frac{4}{5}-\frac{23}{\not7_1}\cdot\frac{\not70^{10}}{13}=\\\\=1\frac{4}{5}-\frac{230}{13}=1\frac{4}{5}-17\frac{9}{13}=-(17\frac{9}{13}-1\frac{4}{5})=\\\\=-(17\frac{45}{65}-1\frac{52}{65})=-(16\frac{110}{65}-1\frac{52}{65})=-15\frac{58}{65}[/tex]
c)
[tex](0,4+1\frac{2}{3})\cdot(-2)^2=(\frac{4}{10}+1\frac{2}{3})\cdot4=\\\\=(\frac{2}{5}+1\frac{2}{3})\cdot4=(\frac{6}{15}+1\frac{10}{15})\cdot4=1\frac{16}{15}\cdot4=\\\\=\frac{31}{15}\cdot4=\frac{124}{15}=8\frac{4}{15}[/tex]
d)
[tex](2\frac{3}{4}-3,5)\cdot(-2^2)=(2\frac{75}{100}-3,5)\cdot(-4)=\\\\=(2,75-3,5)\cdot(-4)=-0,75\cdot(-4)=3[/tex]
Pozdrawiam!
