Cześć ;-)
Obliczenia
[tex]\frac{1}{3}:3+5:\frac{1}{5}=\frac{1}{3}\cdot\frac{1}{3}+5\cdot5=\frac{1}{9}+25=25\frac{1}{9}\\\\(1\frac{1}{8}-\frac{1}{2})\cdot(\frac{3}{5}+\frac{1}{3})=(\frac{9}{8}-\frac{4}{8})\cdot(\frac{9}{15}+\frac{5}{15})=\frac{\not5^1}{\not8_4}\cdot\frac{\not14^7}{\not15_3}=\frac{7}{12}[/tex]
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