a)
[tex]10 \frac{1}{6} + 4 \frac{3}{8} = \frac{61}{6} + \frac{35}{8} = \frac{488 + 210}{48} = \frac{698}{48} = \frac{349}{24} [/tex]
b)
[tex]5 \frac{3}{5} - 4 \frac{2}{7} = \frac{28}{5} - \frac{30}{7} = \frac{196 - 150}{35} = \frac{46}{35} [/tex]
c)
[tex]10 \frac{1}{8} - 3 \frac{2}{3} = \frac{81}{8} - \frac{11}{3} = \frac{243 - 88}{24} = \frac{155}{24} [/tex]
