Odpowiedź:
Szczegółowe wyjaśnienie:
a)
3log(3) √2 - 1/2 log(3) 2 - log(3) 6 = log(3) 2^(3/2) - log(3) 2^(1/2) - log3 6 =
log(3) 2 - log(3) 6 = log(3) 1/3 = -1
b)
log(2) 0,08 + 4log(2) 5 - log(2) 12,5 = log(2) (2/25) + log(2) 5^(4) -
-log(2) 12,5 = log(2) 50 - log(2) 12,5 = log(2) 4 = 2
c)
log(5) 2,4 + 2/3log(5) 0,125 - log(5) 3 =log(5) 2,4 + 2/3log(5) (1/8) - log(5) 3 =
=log(5) 2,4 + log(5) [(1/2)^3]^(2/3) - log(5) 3 = log(5) 2,4 + log(5) (1/4) - log(5) 3 = log(5) 0,6 - log(5) 3 = log(5) 0,2 = log(5) 1/5 = -1
d)
log 2,5 - 3/2log 0,25 + log 50 = log 2,5 - log (1/4)^(3/2) + log 50 =
= log 2,5 - log (1/8) + log 50 = log 20 + log 50 = log 1000 = 3