Pomoże ktoś dam naj Klasa 7 stona 25 zadanie 2 podręcznik z plusem matematyka


Pomoże Ktoś Dam Naj Klasa 7 Stona 25 Zadanie 2 Podręcznik Z Plusem Matematyka class=

Odpowiedź :

A: [tex]\frac{1}{7} + \frac{5}{14} = \frac{2}{14} + \frac{5}{14} = \frac{7}{14} = \frac{1}{2} \\[/tex]

B: [tex]\frac{3}{4} + \frac{5}{12} = \frac{9}{12} + \frac{5}{12} = \frac{14}{12} = 1 \frac{2}{12} = 1 \frac{1}{6}[/tex]

C: [tex]\frac{8}{9} - \frac{5}{18} = \frac{16}{18} - \frac{5}{18} = \frac{11}{18}[/tex]

D: [tex]\frac{1}{3} + \frac{3}{4} = \frac{4}{12} + \frac{9}{12} = \frac{13}{12} = 1 \frac{1}{12} \\[/tex]

E: [tex]\frac{3}{5} - \frac{1}{2} = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}[/tex]

F: [tex]1 \frac{1}{2} - \frac{1}{3} = \frac{3}{2} - \frac{1}{3} = \frac{9}{6} - \frac{2}{6} = \frac{7}{6} = 1 \frac{1}{6}[/tex]

G: [tex]1 \frac{1}{2} +\frac{3}{8} = \frac{3}{2} + \frac{3}{8} = \frac{12}{8} + \frac{3}{8} = \frac{15}{8} = 1 \frac{7}{8}[/tex]

H: [tex]1 \frac{1}{3} - \frac{2}{9} = \frac{4}{3} - \frac{2}{9} = \frac{12}{9} - \frac{2}{9} = \frac{10}{9} = 1\frac{1}{9}[/tex]

I : [tex]2 \frac{3}{5} - \frac{7}{10} = \frac{13}{5} - \frac{7}{10} = \frac{26}{10} - \frac{7}{10} = \frac{19}{10} = 1 \frac{9}{10} \\[/tex]

J: [tex]\frac{5}{6} - \frac{1}{4} = \frac{10}{12} - \frac{3}{12} = \frac{7}{12}[/tex]

K: [tex]1 \frac{1}{6} - \frac{7}{9} = \frac{7}{6} - \frac{7}{9} = \frac{21}{18} -\frac{14}{21} = \frac{7}{21} =\frac{1}{3}[/tex]

L: [tex]2 \frac{3}{8} - 1 \frac{5}{6} = \frac{19}{8} - \frac{11}{6} = \frac{57}{24} - \frac{44}{24} = \frac{13}{24}[/tex]