Odpowiedź:
[tex]\huge\boxed{\boxed{\text{wynik}\longrightarrow1\frac{13}{15}}}[/tex]
Szczegółowe wyjaśnienie:
[tex]6\frac{2}{3}\cdot0,25+\frac{1}{5}=\frac{6\cdot3+2}{3}\cdot\frac{25}{100}+\frac{1}{5}=\frac{18+2}{3}\cdot\frac{25:25}{100:25}+\frac{1}{5}=\\\\=\frac{\not20^5}{3}\cdot\frac{1}{\not4_1}+\frac{1}{5}=\frac{5}{3}+\frac{1}{5}=1\frac{2}{3}+\frac{1}{5}=1\frac{2\cdot5}{3\cdot5}+\frac{1\cdot3}{5\cdot3}=1\frac{10}{15}+\frac{3}{15}=1\frac{13}{15}[/tex]