[tex]dane:\\V = 10 \ cm^{3}\\d = 19,3\frac{g}{cm^{3}} \ - \ gestosc \ zlota\\szukane:\\m = ?\\\\\\d = \frac{m}{V} \ \ /\cdot V\\\\m = V\cdot d\\\\m = 10 \ cm^{3}\cdot19,3\frac{g}{cm^{3}}\\\\\underline{m = 193 \ g = 0,193 \ kg}[/tex]
