Zad.10.
[tex]a)~~-4\cdot(-2-11)=-4\cdot(-13)=52\\b)~~-7+2\cdot(-5)=-7-10=-17\\c)~~-11-12:(-6)=-11+2=-9\\d)~~-8-5\cdot(-4)-4\cdot(-6)=-8+20+24=36\\e)~~\frac{7+(-15)}{2}+\frac{-8}{-3-1}=\frac{-8}{2}+\frac{-8}{-4}=-4+2=-2\\f)~~\frac{-11-9}{-4}-\frac{6-12}{-3}=\frac{-20}{-4}-\frac{-18}{-3}=5-6=-1[/tex]
