Odpowiedź:
[tex]\dfrac{1\frac{7}{9}-1\frac{1}{3}}{\frac{5}{9}-0,6:1\frac{4}{5}}=\dfrac{1\frac{7}{9}-1\frac{3}{9}}{\frac{5}{9}-\frac{6}{10}:\frac{9}{5}}=\dfrac{\frac{4}{9}}{\frac{5}{9}-\frac{\not3^1}{\not5_{1}}\cdot\frac{\not5^1}{\not9_{3}}}=\dfrac{\frac{4}{9}}{\frac{5}{9}-\frac{1}{3}}=\dfrac{\frac{4}{9}}{\frac{5}{9}-\frac{3}{9}}=\dfrac{\frac{4}{9}}{\frac{2}{9}}=\frac{4}{9}:\frac{2}{9}=\\\\\\=\frac{\not4^2}{\not9_{1}}\cdot\frac{\not9^1}{\not2_{1}}=2[/tex]
