Odpowiedź:
[tex]a)\ \ 2^3=2\cdot2\cdot2=8\\\\b)\ \ (\frac{3}{5})^2=\frac{3^2}{5^2}=\frac{9}{25}\\\\c)\ \ (-1)^5=-1\\\\d)\ \ (-7)^0=1\\\\e)\ \ (1\frac{2}{5})^2=(\frac{7}{5})^2=\frac{7^2}{5^2}=\frac{49}{25}=1\frac{24}{25}\\\\f)\ \ (-2\frac{1}{2})^3=(-\frac{5}{2})^3=-\frac{5^3}{2^3}=-\frac{125}{8}-15\frac{5}{8}\\\\g)\ \ -1,2^2=-(\frac{12}{10})^2=-(\frac{6}{5})^2=-\frac{6^2}{5^2}=-\frac{36}{25}=-1\frac{11}{25}\\\\h)\ \ -4^3=-4\cdot4\cdot4=-64[/tex]
